3x^3-9x^2-11x-4/x-3

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Solution for 3x^3-9x^2-11x-4/x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x^3-(9*x^2)-(11*x)-(4/x)-3 = 0

3*x^3-9*x^2-11*x-4*x^-1-3 = 0

3*x^3-9*x^2-11*x^1-4*x^-1-3*x^0 = 0

(3*x^4-9*x^3-11*x^2-3*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^4-9*x^3-11*x^2-3*x^1-4*x^0) = 0

x^1

3*x^4-9*x^3-11*x^2-3*x-4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

3*x^4-9*x^3-11*x^2-3*x-4 = -24

1

-1

x = -1

3*x^4-9*x^3-11*x^2-3*x-4 = 0

-1

x+1

3*x^3-12*x^2+x-4

3*x^4-9*x^3-11*x^2-3*x-4

x+1

-3*x^4-3*x^3

-12*x^3-11*x^2-3*x-4

12*x^3+12*x^2

x^2-3*x-4

-x^2-x

-4*x-4

4*x+4

0

3*x^3-12*x^2+x-4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

3*x^3-12*x^2+x-4 = -12

1

-1

x = -1

3*x^3-12*x^2+x-4 = -20

-1

2

x = 2

3*x^3-12*x^2+x-4 = -26

2

-2

x = -2

3*x^3-12*x^2+x-4 = -78

-2

4

x = 4

3*x^3-12*x^2+x-4 = 0

4

x-4

3*x^2+1

3*x^3-12*x^2+x-4

x-4

12*x^2-3*x^3

x-4

4-x

0

3*x^2+1 = 0

DELTA = 0^2-(1*3*4)

DELTA = -12

DELTA < 0

x in { -1, 4} 

x in { -1, 4 }

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